18x^2+36=54x^2

Solution for 18x^2+36=54x^2 equation:

18x^2+36=54x^2

We move all terms to the left:

18x^2+36-(54x^2)=0

We add all the numbers together, and all the variables

-36x^2+36=0

a = -36; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-36)·36
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-36}=\frac{-72}{-72}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-36}=\frac{72}{-72}
=-1
$